Refer to the following code block:01 let array = [1, 2, 3, 4, 5, 6,...

This code uses:

A for...of loop to iterate over values in array.

break to exit the loop entirely when output > 10.

continue to skip even numbers.

It sums only certain numbers into output.

Let’s walk through the loop step by step.

Initial values:

array = [1,2,3,4,5,6,7,8,9,10,11]

output = 0

Loop: for (let num of array) { ... }

First iteration: num = 1

Line 05: if (output > 10) → 0 > 10 is false → no break.

Line 08: if (num % 2 == 0) → 1 % 2 == 1, not 0, so false → no continue.

Line 11: output += num → output = 0 + 1 = 1.

Second iteration: num = 2

output > 10 → 1 > 10 is false → no break.

num % 2 == 0 → 2 % 2 == 0, so true → continue.

Because of continue, line 11 is skipped.

output remains 1.

Third iteration: num = 3

output > 10 → 1 > 10 is false.

num % 2 == 0 → 3 % 2 == 1, false → no continue.

output += num → output = 1 + 3 = 4.

Fourth iteration: num = 4

output > 10 → 4 > 10 is false.

num % 2 == 0 → 4 % 2 == 0, true → continue.

Skip sum; output remains 4.

Fifth iteration: num = 5

output > 10 → 4 > 10 is false.

num % 2 == 0 → 5 % 2 == 1, false.

output += num → output = 4 + 5 = 9.

Sixth iteration: num = 6

output > 10 → 9 > 10 is false.

num % 2 == 0 → 6 % 2 == 0, true → continue.

output remains 9.

Seventh iteration: num = 7

output > 10 → 9 > 10 is false.

num % 2 == 0 → 7 % 2 == 1, false.

output += num → output = 9 + 7 = 16.

Eighth iteration would be num = 8, but:

At the top of the loop body, line 05 is checked again:

if (output > 10) → 16 > 10 is true, so break; is executed.

When break runs:

The loop terminates immediately.

No further iterations (for num = 8, 9, 10, 11) are executed.

Therefore, output stays at 16.

Final value of output after the loop ends is 16.

This matches option A.

Why other options do not match:

B. 25: Would require adding more odd numbers (e.g., 9, 11) after 7, but the loop stops early due to output > 10.

C. 11: Would be smaller; the actual sum of 1 + 3 + 5 + 7 until break is 16.

D. 36: Would require summing many more values (e.g., most or all odd numbers up to 11), but again, the break condition stops the loop once output exceeds 10.

So:

Answer: A

JavaScript knowledge / Study Guide references (concept names only, no links):

for...of loop over arrays

break statement in loops (terminating a loop early)

continue statement in loops (skipping to the next iteration)

Modulo operator % to test even and odd numbers

Step-by-step execution and control flow in loops