Refer to the code below:let productSKU = ' 8675309 ' ;A developer has a requirement...

We start with:

let productSKU = ' 8675309 ' ;

The requirement:

Final SKU string:

Length: 19 characters.

Starts with ' sku ' .

Remaining characters are digits padded with zeros on the left (to reach total length).

We can use String.prototype.padStart and String.prototype.padEnd:

str.padStart(targetLength, padString)

If str.length < targetLength, it adds padString to the start until the length is targetLength.

str.padEnd(targetLength, padString)

Similar, but adds padString to the end.

We want a pattern like:

First, pad the numeric part out to a fixed length with zeros.

Then, pad to total length with ' sku ' at the start.

Analyze Option B

productSKU = productSKU.padStart(16, ' 0 ' ).padStart(19, ' sku ' );

Step 1: productSKU.padStart(16, ' 0 ' )

Initial productSKU is ' 8675309 ' (length 7).

After padStart(16, ' 0 ' ), we pad zeros on the left to reach length 16.

We need 16 − 7 = 9 zeros:

Result after step 1:

productSKU === ' 0000000008675309 ' // length 16

Step 2: .padStart(19, ' sku ' )

Now productSKU has length 16.

We call padStart(19, ' sku ' ):

We need 19 − 16 = 3 extra characters.

The pad string ' sku ' is exactly 3 characters, so it is added as-is at the start.

Result after step 2:

productSKU === ' sku0000000008675309 ' // length 19

This satisfies:

Length 19.

Starts with ' sku ' .

Remaining characters are zeros plus the original digits, i.e. a zero-padded numeric section.

While the literal sample sku000000008675309 in the text has a slightly different count of zeros, Option B follows the requirement pattern:

3 characters of ' sku '

Numeric part padded with zeros to make 16 characters total for the numeric part

3 + 16 = 19 total characters

Option B matches the intended logic using padStart and padEnd.

Why the other options are incorrect

Option A:

productSKU = productSKU.padEnd(16, ' 0 ' ).padStart( ' sku ' );

padEnd(16, ' 0 ' ) produces ' 8675309000000000 ' (original number followed by zeros).

padStart( ' sku ' ) is invalid usage:

padStart takes a numeric target length as the first argument, not a string.

Passing ' sku ' as the first argument leads to type coercion that does not achieve the intended behavior.

This will not reliably produce the desired SKU.

Option C:

productSKU = productSKU.padEnd(16, ' 0 ' ).padStart(19, ' sku ' );

First padEnd(16, ' 0 ' ) from ' 8675309 ' gives ' 8675309000000000 ' (length 16, zeros at the end).

Then padStart(19, ' sku ' ) adds 3 chars ' sku ' at the front:

Result: ' sku8675309000000000 ' .

This string starts with ' sku ' , but the zeros are at the end of the digits, not padding the numeric part on the left as desired.

Option D:

productSKU = productSKU.padStart(19, ' 0 ' ).padStart( ' sku ' );

First padStart(19, ' 0 ' ) pads zeros at the left to make the length 19.

Then padStart( ' sku ' ) again incorrectly uses a string where a numeric targetLength is required.

This will not produce the correct SKU format.

Therefore, the only option that correctly uses padStart to create a 16-character zero-padded numeric portion and then a 19-character string starting with ' sku ' is:

Answer: B

References / Study Guide concepts (no links):

String.prototype.padStart(targetLength, padString)

String.prototype.padEnd(targetLength, padString)

String length calculations

Left-padding numeric strings with zeros

Building prefixed identifiers with fixed total length