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Which of the following is a reason for using Jensen-Shannon (JS) distance over a Kolmogorov-Smirnov...

Which of the following is a reason for using Jensen-Shannon (JS) distance over a Kolmogorov-Smirnov (KS) test for numeric feature drift detection?

A.

All of these reasons

B.

JS is not normalized or smoothed

C.

None of these reasons

D.

JS is more robust when working with large datasets

E.

JS does not require any manual threshold or cutoff determinations

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