Referring to the exhibit, which statement is correct?
A.
The device with the highest IP address is elected as the DR.
B.
The OSPF state will be stuck in the Exstart state
C.
The OSPF state will be stuck in the 2Nay state
D.
The device with the lowest IP address is elected as the DR.
The Answer Is:
C
This question includes an explanation.
Explanation:
In OSPF, the election of a Designated Router (DR) and a Backup Designated Router (BDR) is mandatory on broadcast and non-broadcast multi-access (NBMA) network types to manage link-state database synchronization efficiently.
The exhibit shows that both device1 and device2 have their OSPF interface priority explicitly set to 0. According to the Junos OS 24.4 OSPF implementation:
Ineligibility (Priority 0): A router with a priority of 0 is strictly ineligible to be elected as a DR or BDR for that segment.
No Election Possible: When every router on a broadcast segment has a priority of 0, the election process cannot complete because there are no eligible candidates to fill the required roles.
State Behavior (Stuck in 2-Way): In OSPF adjacency formation, the 2-Way state indicates that bidirectional communication has been established (each router has seen itself in the other's Hello packets). However, to progress to the Exstart and Exchange states on a multi-access network, routers must first identify a DR and BDR.
Result: Since neither router can become the DR, they both wait indefinitely for a third party (with priority > 0) to take the lead. Consequently, the OSPF adjacency will be stuck in the 2-Way state. Adjacencies only reach the Full state with the DR and BDR; routers in a "DROther" role remain in 2-Way with each other.
Option A and D are incorrect because the router ID (IP address) only acts as a tiebreaker if priorities are equal and greater than 0. Option B is incorrect because routers cannot reach the Exstart state (where they negotiate master/slave for database exchange) without first having a DR/BDR elected.
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