The correct answers are B and D .
A strong test case checks whether the actual output matches the expected behavior of the function.
For Option B :
let res = fizzbuzz(15);
console.assert(res === ' fizzbuzz ' );
The number 15 is divisible by both 3 and 5:
15 % 3 === 0
15 % 5 === 0
So the correct return value is:
' fizzbuzz '
That makes option B a valid test.
For Option D :
let res = fizzbuzz(Infinity);
console.assert(res === ' ' );
Infinity is not a normal finite divisible number. In JavaScript:
Infinity % 3
Infinity % 5
produce NaN, and comparisons such as:
Infinity % 3 === 0
are false.
So a typical fizzbuzz implementation would not treat Infinity as divisible by 3 or 5, meaning it should return:
' '
That makes option D a valid test for the “neither divisible by 3 nor 5” path.
Now compare the incorrect options:
Option A is wrong because:
fizzbuzz(3)
should return:
' fizz '
not:
' buzz '
Option C is wrong because the function specification says the function returns strings such as ' fizz ' , ' buzz ' , ' fizzbuzz ' , or ' ' . It does not say the function returns numeric NaN.
So this assertion is not appropriate:
console.assert(isNaN(res));
Therefore, the verified answers are B and D .