A developer has a fizzbuzz function that, when passed in a number, returns the following:'...

First, recall the fizzbuzz rules:

If n divisible by 3 and not by 5 → return ' fizz ' .

If n divisible by 5 and not by 3 → return ' buzz ' .

If n divisible by both 3 and 5 → return ' fizzbuzz ' .

Otherwise → return ' ' (empty string).

Evaluate each test:

Option A:

let res = fizzbuzz(true);

console.assert(res === ' ' );

In JavaScript, when using arithmetic operations with true, it is coerced to the number 1. A typical implementation of fizzbuzz would treat the argument as a number and compute:

true % 3 → 1 % 3 → 1

true % 5 → 1 % 5 → 1

So true is effectively treated as 1, which is divisible by neither 3 nor 5. The function should return ' ' . The assertion res === ' ' will pass.

This test covers the scenario “neither divisible by 3 nor 5”.

Option B:

let res = fizzbuzz(3);

console.assert(res === ' ' );

3 is divisible by 3 but not by 5.

According to fizzbuzz rules, fizzbuzz(3) should return ' fizz ' .

This test expects ' ' , so it is incorrect; the assertion would fail in a correct implementation.

Option C:

let res = fizzbuzz(5);

console.assert(res === ' fizz ' );

5 is divisible by 5 but not by 3.

According to fizzbuzz rules, fizzbuzz(5) should return ' buzz ' .

This test expects ' fizz ' , so it is incorrect.

Option D:

let res = fizzbuzz(15);

console.assert(res === ' fizzbuzz ' );

15 is divisible by both 3 and 5.

According to fizzbuzz rules, fizzbuzz(15) should return ' fizzbuzz ' .

This assertion correctly matches the expected result, so it is a proper test case.

Thus, the two test cases that correctly test valid fizzbuzz behavior are:

Answer: A, D

Study Guide / Concept References (no links):

Modulo operator (%) for divisibility checks

Truthy/number coercion of boolean true in arithmetic (Number(true) === 1)

Designing unit tests with console.assert

Typical fizzbuzz logic structure and expected outputs