The correct answer is D. The inbound IPsec SA was copied to the NPU.
The exhibit shows:
npu_flag=02
dec_npuid=1
enc_npuid=0
The study guide gives the exact meaning of the npu_flag field:
npu_flag=00 = Both IPsec SAs loaded to the kernel
npu_flag=01 = Outbound IPsec SA copied to NPU
npu_flag=02 = Inbound IPsec SA copied to NPU
npu_flag=03 = Both outbound and inbound IPsec SAs copied to NPU
It also explains: “If the first IPsec packet is inbound and can be offloaded, the inbound SA is copied to the NPU and the npu_flag changes to 02. After both SAs are copied to the NPU, the npu_flag changes to 03.”
So with npu_flag=02, only the inbound SA has been copied to the NPU. That makes D correct.
Why the other options are wrong:
A is wrong because outbound-only offload would be npu_flag=01, not 02
C is wrong because both directions offloaded would be npu_flag=03, not 02
B is wrong because dec_npuid=1 identifies the NPU ID used for decryption, but it does not state that the processor is specifically NP6 . The study guide only maps the offload state through the npu_flag values in this context, not the NPU model from this field alone
So the verified answer is: D .
