The following question requires your selection of CCC/CCE Scenario 4 (2.

Steel:

Year 1 inflation: 2.5%

Year 2 inflation: 2.5%

Year 3 inflation: 3.0%

Total cumulative inflation for Steel over 2.5 years: Cumulative Inflation=(1+0.025)×(1+0.025)×(1+0.03)=1.025×1.025×1.03=1.080625×1.03≈1.11304\text{Cumulative Inflation} = (1 + 0.025) \times (1 + 0.025) \times (1 + 0.03) = 1.025 \times1.025 \times 1.03 = 1.080625 \times 1.03 \approx 1.11304Cumulative Inflation=(1+0.025)×(1+0.025)×(1+0.03)=1.025×1.025×1.03=1.080625×1.03≈1.11304

Steel cost component: 0.3 \times $350,000 = $105,000

Adjusted cost: $105,000 \times 1.11304 ≈ $116,869.20

Copper:

Year 1 inflation: 1.0%

Year 2 inflation: 1.5%

Year 3 inflation: 2.0%

Total cumulative inflation for Copper over 2.5 years: Cumulative Inflation=(1+0.01)×(1+0.015)×(1+0.02)=1.01×1.015×1.02≈1.04515×1.02≈1.0651\text{Cumulative Inflation} = (1 + 0.01) \times (1 + 0.015) \times (1 + 0.02) = 1.01 \times 1.015 \times 1.02 ≈ 1.04515 \times 1.02 ≈ 1.0651Cumulative Inflation=(1+0.01)×(1+0.015)×(1+0.02)=1.01×1.015×1.02≈1.04515×1.02≈1.0651

Copper cost component: 0.3 \times $350,000 = $105,000

Adjusted cost: $105,000 \times 1.0651 ≈ $111,835.50

Manufacturing Labor:

Year 1 inflation: 2.5%

Year 2 inflation: 3.0%

Year 3 inflation: 3.5%

Total cumulative inflation for Manufacturing Labor over 2.5 years: Cumulative Inflation=(1+0.025)×(1+0.03)×(1+0.035)=1.025×1.03×1.035≈1.05625×1.035≈1.09138\text{Cumulative Inflation} = (1 + 0.025) \times (1 + 0.03) \times (1 + 0.035) = 1.025 \times 1.03 \times 1.035 ≈ 1.05625 \times 1.035 ≈ 1.09138Cumulative Inflation=(1+0.025)×(1+0.03)×(1+0.035)=1.025×1.03×1.035≈1.05625×1.035≈1.09138

Labor cost component: 0.4 \times $350,000 = $140,000

Adjusted cost: $140,000 \times 1.09138 ≈ $152,793.20

Final Price:

Final Price=116,869.20+111,835.50+152,793.20≈381,497.90\text{Final Price} = 116,869.20 + 111,835.50 + 152,793.20 ≈ 381,497.90Final Price=116,869.20+111,835.50+152,793.20≈381,497.90

The closest option:Answer:D. $378,750