If an object is placed 1 m (3 ft) away from a light source and...

If an object is placed 1 meter (3 feet) away from a light source with a lux level of 3200 lux, the lux level decreases according to the inverse square law of light. At a distance of 8 meters (24 feet), the lux level can be calculated as:

New Lux Level=3200 lux(8/1)2=3200 lux64=50 lux\text{New Lux Level} = \frac{3200 \text{ lux}}{(8/1)^2} = \frac{3200 \text{ lux}}{64} = 50 \text{ lux}New Lux Level=(8/1)23200 lux​=643200 lux​=50 lux

Thus, at 8 meters, the light intensity drops significantly to 50 lux.