Given:javarecord WithInstanceField(String foo, int bar) {double fuz;}record WithStaticField(String foo, int bar) {static double wiz;}record ExtendingClass(String...

In Java, records are a special kind of class designed to act as transparent carriers for immutabledata. They automatically provide implementations for equals(), hashCode(), and toString(), and their fields are final and private by default.

Option A: ExtendingClass

Analysis: Records in Java implicitly extend java.lang.Record and cannot extend any other class because Java does not support multiple inheritance. Attempting to extend another class, such as Exception, will result in a compilation error.

Conclusion: Does not compile.

Option B: WithInstanceField

Analysis: Records do not allow the declaration of instance fields outside of their components. The declaration of double fuz; is not permitted and will cause a compilation error.

Conclusion: Does not compile.

Option C: ImplementingInterface

Analysis: Records can implement interfaces. In this case, ImplementingInterface implements Cloneable, which is valid.

Conclusion: Compiles successfully.