Given:javapublic class SpecialAddition extends Addition implements Special {public static void main(String[] args) {System.

1. Why does the compilation fail?

The interface Special contains bar as int bar = 1;.

In Java, all interface fields are implicitly public, static, and final.

This means that bar is a constant (final variable).

The method add() contains bar--, which attempts to modify bar.

Since bar is final, it cannot be modified, causing acompilation error.

2. Correcting the Code

To make the code compile, bar must not be final. One way to fix this:

java

class SpecialImpl implements Special {

int bar = 1;

}

Or modify the add() method:

java

int add() {

return --foo + bar; // No modification of bar

}

Thus, the correct answer is:Compilation fails.

References:

Java SE 21 - Interfaces

Java SE 21 - Final Variables